If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(1/49)^x-3=2401
We move all terms to the left:
(1/49)^x-3-(2401)=0
Domain of the equation: 49)^x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+1/49)^x-3-2401=0
We add all the numbers together, and all the variables
(+1/49)^x-2404=0
We multiply all the terms by the denominator
(+1-2404*49)^x=0
We add all the numbers together, and all the variables
(-117795)^x=0
| -8-9v=7-6v | | 12=6n-6n | | 9.57+14s=19.8s+4.93 | | 34=15x | | -5-9p=-10p | | -8m+3m=5 | | d-37=35 | | 15k+11=11+19k | | x=x/75-75 | | x+2x+x=170 | | 18m=17m+19 | | 3.2w=-13 | | -3x+12=9x+4 | | 1(2e+1)=2e(1+2) | | -2-9c-6=-13c+12 | | 25=6x+2+5 | | -1(3x-12)=9x-4 | | x/3+(3/4*x)=26 | | 4x+31=x+46 | | 7x+5(1-7x)=89 | | 11p^2-14p+9p^2=0 | | 6x+17=3x+32 | | 1r+2r=3r+4r | | 6-4z=-z | | 0=4x^2-484 | | 92=2k | | 5p-9=-1+9p | | 60=-5k | | 4(4w+5)÷5=-9 | | -7g-9=9+7g-5g | | 22=y-24 | | 20x-2=66 |